1 条题解
-
1
#include<iostream> #include<cstdio> using namespace std; int main(){ double jiage[11],shuliang[11],zongjia=0; jiage[1]=28.9; jiage[2]=32.7; jiage[3]=45.6; jiage[4]=78; jiage[5]=35; jiage[6]=86.2; jiage[7]=27.8; jiage[8]=43; jiage[9]=56; jiage[10]=65; for(int i = 1;i<=10;i++){ cin>>shuliang[i]; } for(int i = 1;i<=10;i++){ zongjia = zongjia+jiage[i]*shuliang[i]; } printf("%.1lf",zongjia); }
- 1
信息
- ID
- 220
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 6
- 标签
- 递交数
- 44
- 已通过
- 14
- 上传者