1 条题解

  • 1
    @ 2023-7-7 17:17:42
    #include<iostream>
    #include<cstdio>
    using namespace std;
    int main(){
        double jiage[11],shuliang[11],zongjia=0;
        jiage[1]=28.9;
        jiage[2]=32.7;
        jiage[3]=45.6;
        jiage[4]=78;
        jiage[5]=35;
        jiage[6]=86.2;
        jiage[7]=27.8;
        jiage[8]=43;
        jiage[9]=56;
        jiage[10]=65;
        for(int i = 1;i<=10;i++){
            cin>>shuliang[i];
        }
        for(int i = 1;i<=10;i++){
            zongjia = zongjia+jiage[i]*shuliang[i];
        }
        printf("%.1lf",zongjia);
    }
    
    • 1

    信息

    ID
    220
    时间
    1000ms
    内存
    128MiB
    难度
    6
    标签
    递交数
    44
    已通过
    14
    上传者